1303324234181 has 2 divisors, whose sum is σ = 1303324234182. Its totient is φ = 1303324234180.

The previous prime is 1303324234141. The next prime is 1303324234183. The reversal of 1303324234181 is 1814324233031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1300295493025 + 3028741156 = 1140305^2 + 55034^2 .

It is a cyclic number.

It is not a de Polignac number, because 1303324234181 - 2¹⁰ = 1303324233157 is a prime.

It is a super-3 number, since 3×1303324234181³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 1303324234183, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1303324234183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651662117090 + 651662117091.

It is an arithmetic number, because the mean of its divisors is an integer number (651662117091).

Almost surely, 2^{1303324234181} is an apocalyptic number.

It is an amenable number.

1303324234181 is a deficient number, since it is larger than the sum of its proper divisors (1).

1303324234181 is an equidigital number, since it uses as much as digits as its factorization.

1303324234181 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 41472, while the sum is 35.

The spelling of 1303324234181 in words is "one trillion, three hundred three billion, three hundred twenty-four million, two hundred thirty-four thousand, one hundred eighty-one".