Base | Representation |
---|---|
bin | 11101101000100110010110… |
… | …101010000101000000101101 |
3 | 122002110202001110222022110212 |
4 | 131220212112222011000231 |
5 | 114040340104403210333 |
6 | 1141110143544312205 |
7 | 36311161632561224 |
oct | 3550462652050055 |
9 | 562422043868425 |
10 | 130333310210093 |
11 | 3858a056916381 |
12 | 1274b575a72665 |
13 | 57954bc4c4583 |
14 | 2428247221cbb |
15 | 101040629e448 |
hex | 768996a8502d |
130333310210093 has 2 divisors, whose sum is σ = 130333310210094. Its totient is φ = 130333310210092.
The previous prime is 130333310210071. The next prime is 130333310210167. The reversal of 130333310210093 is 390012013333031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 97338705817444 + 32994604392649 = 9866038^2 + 5744093^2 .
It is a cyclic number.
It is not a de Polignac number, because 130333310210093 - 212 = 130333310205997 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130333310210393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65166655105046 + 65166655105047.
It is an arithmetic number, because the mean of its divisors is an integer number (65166655105047).
Almost surely, 2130333310210093 is an apocalyptic number.
It is an amenable number.
130333310210093 is a deficient number, since it is larger than the sum of its proper divisors (1).
130333310210093 is an equidigital number, since it uses as much as digits as its factorization.
130333310210093 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13122, while the sum is 32.
The spelling of 130333310210093 in words is "one hundred thirty trillion, three hundred thirty-three billion, three hundred ten million, two hundred ten thousand, ninety-three".
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