Base | Representation |
---|---|
bin | 1011110110101000111100… |
… | …0100100101100010110111 |
3 | 1201010222022020212212122221 |
4 | 2331222033010211202313 |
5 | 3202014230231322221 |
6 | 43415232450103211 |
7 | 2513425044425305 |
oct | 275521704454267 |
9 | 51128266785587 |
10 | 13033331120311 |
11 | 417544a703817 |
12 | 1565b4427ab07 |
13 | 73706520a708 |
14 | 330b60a2b275 |
15 | 17906095e541 |
hex | bda8f1258b7 |
13033331120311 has 2 divisors, whose sum is σ = 13033331120312. Its totient is φ = 13033331120310.
The previous prime is 13033331120269. The next prime is 13033331120351. The reversal of 13033331120311 is 11302113333031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13033331120311 - 235 = 12998971381943 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13033331120351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6516665560155 + 6516665560156.
It is an arithmetic number, because the mean of its divisors is an integer number (6516665560156).
Almost surely, 213033331120311 is an apocalyptic number.
13033331120311 is a deficient number, since it is larger than the sum of its proper divisors (1).
13033331120311 is an equidigital number, since it uses as much as digits as its factorization.
13033331120311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1458, while the sum is 25.
Adding to 13033331120311 its reverse (11302113333031), we get a palindrome (24335444453342).
The spelling of 13033331120311 in words is "thirteen trillion, thirty-three billion, three hundred thirty-one million, one hundred twenty thousand, three hundred eleven".
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