Base | Representation |
---|---|
bin | 111100101100001111… |
… | …0111110001111110101 |
3 | 110110102011112111010022 |
4 | 1321120132332033311 |
5 | 4113410341030143 |
6 | 135512511534525 |
7 | 12262533516164 |
oct | 1713036761765 |
9 | 413364474108 |
10 | 130333533173 |
11 | 50301977588 |
12 | 2131452a445 |
13 | c3a101383c |
14 | 64458cb3db |
15 | 35cc298268 |
hex | 1e587be3f5 |
130333533173 has 2 divisors, whose sum is σ = 130333533174. Its totient is φ = 130333533172.
The previous prime is 130333533137. The next prime is 130333533193. The reversal of 130333533173 is 371335333031.
It is a happy number.
Together with previous prime (130333533137) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 111979244689 + 18354288484 = 334633^2 + 135478^2 .
It is a cyclic number.
It is not a de Polignac number, because 130333533173 - 210 = 130333532149 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130333533193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65166766586 + 65166766587.
It is an arithmetic number, because the mean of its divisors is an integer number (65166766587).
Almost surely, 2130333533173 is an apocalyptic number.
It is an amenable number.
130333533173 is a deficient number, since it is larger than the sum of its proper divisors (1).
130333533173 is an equidigital number, since it uses as much as digits as its factorization.
130333533173 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 76545, while the sum is 35.
The spelling of 130333533173 in words is "one hundred thirty billion, three hundred thirty-three million, five hundred thirty-three thousand, one hundred seventy-three".
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