Base | Representation |
---|---|
bin | 11101101000100111000000… |
… | …010111110001001001010000 |
3 | 122002110210212020212000201221 |
4 | 131220213000113301021100 |
5 | 114040343023033200300 |
6 | 1141110341224334424 |
7 | 36311215161260152 |
oct | 3550470027611120 |
9 | 562423766760657 |
10 | 130334010053200 |
11 | 3858a385968908 |
12 | 1274b730314414 |
13 | 57955a14aa415 |
14 | 24282b2158ad2 |
15 | 101044794031a |
hex | 7689c05f1250 |
130334010053200 has 60 divisors (see below), whose sum is σ = 313128573746560. Its totient is φ = 52133418449280.
The previous prime is 130334010053173. The next prime is 130334010053207. The reversal of 130334010053200 is 2350010433031.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130334010053207) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 190706497 + ... + 191388703.
Almost surely, 2130334010053200 is an apocalyptic number.
130334010053200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
130334010053200 is an abundant number, since it is smaller than the sum of its proper divisors (182794563693360).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130334010053200 is a wasteful number, since it uses less digits than its factorization.
130334010053200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1159844 (or 1159833 counting only the distinct ones).
The product of its (nonzero) digits is 3240, while the sum is 25.
Adding to 130334010053200 its reverse (2350010433031), we get a palindrome (132684020486231).
The spelling of 130334010053200 in words is "one hundred thirty trillion, three hundred thirty-four billion, ten million, fifty-three thousand, two hundred".
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