Base | Representation |
---|---|
bin | 11101101000101100110010… |
… | …010010000111101000110111 |
3 | 122002111101212202201000122011 |
4 | 131220230302102013220313 |
5 | 114040443230313024031 |
6 | 1141113245122345051 |
7 | 36311525030203513 |
oct | 3550546222075067 |
9 | 562441782630564 |
10 | 130340216142391 |
11 | 38591a80060542 |
12 | 127509827bb187 |
13 | 5796050182c48 |
14 | 2428700493143 |
15 | 10106ac6d66b1 |
hex | 768b32487a37 |
130340216142391 has 2 divisors, whose sum is σ = 130340216142392. Its totient is φ = 130340216142390.
The previous prime is 130340216142361. The next prime is 130340216142469. The reversal of 130340216142391 is 193241612043031.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130340216142391 - 27 = 130340216142263 is a prime.
It is a super-3 number, since 3×1303402161423913 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130340216142361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65170108071195 + 65170108071196.
It is an arithmetic number, because the mean of its divisors is an integer number (65170108071196).
Almost surely, 2130340216142391 is an apocalyptic number.
130340216142391 is a deficient number, since it is larger than the sum of its proper divisors (1).
130340216142391 is an equidigital number, since it uses as much as digits as its factorization.
130340216142391 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 93312, while the sum is 40.
The spelling of 130340216142391 in words is "one hundred thirty trillion, three hundred forty billion, two hundred sixteen million, one hundred forty-two thousand, three hundred ninety-one".
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