Base | Representation |
---|---|
bin | 1011110110101011111010… |
… | …1100000111100010001100 |
3 | 1201011001100221010210110010 |
4 | 2331222332230013202030 |
5 | 3202022344240343200 |
6 | 43415444025113220 |
7 | 2513453615045415 |
oct | 275527654074214 |
9 | 51131327123403 |
10 | 13034130012300 |
11 | 417581a658131 |
12 | 1566127928810 |
13 | 737161893177 |
14 | 330bd8b8880c |
15 | 1790aab68150 |
hex | bdabeb0788c |
13034130012300 has 72 divisors (see below), whose sum is σ = 37715764883776. Its totient is φ = 3475428644160.
The previous prime is 13034130012287. The next prime is 13034130012373. The reversal of 13034130012300 is 321003143031.
It is a super-3 number, since 3×130341300123003 (a number of 40 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 964239 + ... + 5195961.
Almost surely, 213034130012300 is an apocalyptic number.
13034130012300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13034130012300 is an abundant number, since it is smaller than the sum of its proper divisors (24681634871476).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13034130012300 is a wasteful number, since it uses less digits than its factorization.
13034130012300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4242007 (or 4242000 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 13034130012300 its reverse (321003143031), we get a palindrome (13355133155331).
The spelling of 13034130012300 in words is "thirteen trillion, thirty-four billion, one hundred thirty million, twelve thousand, three hundred".
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