Base | Representation |
---|---|
bin | 10010111101111001100… |
… | …010010111010001100101 |
3 | 11121121100011122211122211 |
4 | 102331321202113101211 |
5 | 132323343010021203 |
6 | 2434440304323421 |
7 | 163111550256322 |
oct | 22757142272145 |
9 | 4547304584584 |
10 | 1303414142053 |
11 | 4628583376a1 |
12 | 19073a913571 |
13 | 95bb053223a |
14 | 4712ab97b49 |
15 | 23d88a22c6d |
hex | 12f79897465 |
1303414142053 has 2 divisors, whose sum is σ = 1303414142054. Its totient is φ = 1303414142052.
The previous prime is 1303414141993. The next prime is 1303414142113. The reversal of 1303414142053 is 3502414143031.
It is a balanced prime because it is at equal distance from previous prime (1303414141993) and next prime (1303414142113).
It can be written as a sum of positive squares in only one way, i.e., 987157499364 + 316256642689 = 993558^2 + 562367^2 .
It is a cyclic number.
It is not a de Polignac number, because 1303414142053 - 217 = 1303414010981 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1303414142353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651707071026 + 651707071027.
It is an arithmetic number, because the mean of its divisors is an integer number (651707071027).
Almost surely, 21303414142053 is an apocalyptic number.
It is an amenable number.
1303414142053 is a deficient number, since it is larger than the sum of its proper divisors (1).
1303414142053 is an equidigital number, since it uses as much as digits as its factorization.
1303414142053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 1303414142053 its reverse (3502414143031), we get a palindrome (4805828285084).
The spelling of 1303414142053 in words is "one trillion, three hundred three billion, four hundred fourteen million, one hundred forty-two thousand, fifty-three".
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