Search a number
-
+
1303414142053 is a prime number
BaseRepresentation
bin10010111101111001100…
…010010111010001100101
311121121100011122211122211
4102331321202113101211
5132323343010021203
62434440304323421
7163111550256322
oct22757142272145
94547304584584
101303414142053
114628583376a1
1219073a913571
1395bb053223a
144712ab97b49
1523d88a22c6d
hex12f79897465

1303414142053 has 2 divisors, whose sum is σ = 1303414142054. Its totient is φ = 1303414142052.

The previous prime is 1303414141993. The next prime is 1303414142113. The reversal of 1303414142053 is 3502414143031.

It is a balanced prime because it is at equal distance from previous prime (1303414141993) and next prime (1303414142113).

It can be written as a sum of positive squares in only one way, i.e., 987157499364 + 316256642689 = 993558^2 + 562367^2 .

It is a cyclic number.

It is not a de Polignac number, because 1303414142053 - 217 = 1303414010981 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1303414142353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651707071026 + 651707071027.

It is an arithmetic number, because the mean of its divisors is an integer number (651707071027).

Almost surely, 21303414142053 is an apocalyptic number.

It is an amenable number.

1303414142053 is a deficient number, since it is larger than the sum of its proper divisors (1).

1303414142053 is an equidigital number, since it uses as much as digits as its factorization.

1303414142053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 1303414142053 its reverse (3502414143031), we get a palindrome (4805828285084).

The spelling of 1303414142053 in words is "one trillion, three hundred three billion, four hundred fourteen million, one hundred forty-two thousand, fifty-three".