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13035344163293 is a prime number
BaseRepresentation
bin1011110110110000011100…
…0011101111000111011101
31201011011111112210001111102
42331230013003233013131
53202032341101211133
643420204320402445
72513525660132264
oct275540703570735
951134445701442
1013035344163293
114176292a49801
121566406476425
137372c62a06ca
14330cb211d5db
1517912c54b7e8
hexbdb070ef1dd

13035344163293 has 2 divisors, whose sum is σ = 13035344163294. Its totient is φ = 13035344163292.

The previous prime is 13035344163203. The next prime is 13035344163299. The reversal of 13035344163293 is 39236144353031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8805094806244 + 4230249357049 = 2967338^2 + 2056757^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13035344163293 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13035344163299) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6517672081646 + 6517672081647.

It is an arithmetic number, because the mean of its divisors is an integer number (6517672081647).

Almost surely, 213035344163293 is an apocalyptic number.

It is an amenable number.

13035344163293 is a deficient number, since it is larger than the sum of its proper divisors (1).

13035344163293 is an equidigital number, since it uses as much as digits as its factorization.

13035344163293 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2099520, while the sum is 47.

The spelling of 13035344163293 in words is "thirteen trillion, thirty-five billion, three hundred forty-four million, one hundred sixty-three thousand, two hundred ninety-three".