Base | Representation |
---|---|
bin | 1011110110110100110001… |
… | …0010101110011010110111 |
3 | 1201011021111111110021102211 |
4 | 2331231030102232122313 |
5 | 3202042230431024003 |
6 | 43420515452514251 |
7 | 2513566523166406 |
oct | 275551422563267 |
9 | 51137444407384 |
10 | 13036505720503 |
11 | 4176829688941 |
12 | 156668b47b987 |
13 | 73744cb25075 |
14 | 330d824c363d |
15 | 1791994e196d |
hex | bdb4c4ae6b7 |
13036505720503 has 2 divisors, whose sum is σ = 13036505720504. Its totient is φ = 13036505720502.
The previous prime is 13036505720479. The next prime is 13036505720531. The reversal of 13036505720503 is 30502750563031.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13036505720503 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13036505720603) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6518252860251 + 6518252860252.
It is an arithmetic number, because the mean of its divisors is an integer number (6518252860252).
Almost surely, 213036505720503 is an apocalyptic number.
13036505720503 is a deficient number, since it is larger than the sum of its proper divisors (1).
13036505720503 is an equidigital number, since it uses as much as digits as its factorization.
13036505720503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 283500, while the sum is 40.
The spelling of 13036505720503 in words is "thirteen trillion, thirty-six billion, five hundred five million, seven hundred twenty thousand, five hundred three".
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