13036843949 has 2 divisors, whose sum is σ = 13036843950. Its totient is φ = 13036843948.

The previous prime is 13036843913. The next prime is 13036843951. The reversal of 13036843949 is 94934863031.

13036843949 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10427473225 + 2609370724 = 102115^2 + 51082^2 .

It is a cyclic number.

It is not a de Polignac number, because 13036843949 - 2¹² = 13036839853 is a prime.

Together with 13036843951, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13036843897 and 13036843906.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13036843909) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6518421974 + 6518421975.

It is an arithmetic number, because the mean of its divisors is an integer number (6518421975).

Almost surely, 2^13036843949 is an apocalyptic number.

It is an amenable number.

13036843949 is a deficient number, since it is larger than the sum of its proper divisors (1).

13036843949 is an equidigital number, since it uses as much as digits as its factorization.

13036843949 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1679616, while the sum is 50.

The spelling of 13036843949 in words is "thirteen billion, thirty-six million, eight hundred forty-three thousand, nine hundred forty-nine".