Base | Representation |
---|---|
bin | 11101101001100100100000… |
… | …000100001100011110011111 |
3 | 122002201010021222221010102022 |
4 | 131221210200010030132133 |
5 | 114042433240222410242 |
6 | 1141200541300250355 |
7 | 36316043361034235 |
oct | 3551444004143637 |
9 | 562633258833368 |
10 | 130400040044447 |
11 | 3860538a0a0608 |
12 | 127604996a09bb |
13 | 579b8952a4364 |
14 | 242b5777c6955 |
15 | 101200e7520d2 |
hex | 76992010c79f |
130400040044447 has 2 divisors, whose sum is σ = 130400040044448. Its totient is φ = 130400040044446.
The previous prime is 130400040044363. The next prime is 130400040044453. The reversal of 130400040044447 is 744440040004031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130400040044447 - 218 = 130400039782303 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130400040004447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65200020022223 + 65200020022224.
It is an arithmetic number, because the mean of its divisors is an integer number (65200020022224).
Almost surely, 2130400040044447 is an apocalyptic number.
130400040044447 is a deficient number, since it is larger than the sum of its proper divisors (1).
130400040044447 is an equidigital number, since it uses as much as digits as its factorization.
130400040044447 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 86016, while the sum is 35.
Adding to 130400040044447 its reverse (744440040004031), we get a palindrome (874840080048478).
The spelling of 130400040044447 in words is "one hundred thirty trillion, four hundred billion, forty million, forty-four thousand, four hundred forty-seven".
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