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130400040044453 is a prime number
BaseRepresentation
bin11101101001100100100000…
…000100001100011110100101
3122002201010021222221010102112
4131221210200010030132211
5114042433240222410303
61141200541300250405
736316043361034244
oct3551444004143645
9562633258833375
10130400040044453
113860538a0a0613
12127604996a0a05
13579b8952a436a
14242b5777c695b
15101200e7520d8
hex76992010c7a5

130400040044453 has 2 divisors, whose sum is σ = 130400040044454. Its totient is φ = 130400040044452.

The previous prime is 130400040044447. The next prime is 130400040044537. The reversal of 130400040044453 is 354440040004031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 94356803070049 + 36043236974404 = 9713743^2 + 6003602^2 .

It is a cyclic number.

It is not a de Polignac number, because 130400040044453 - 242 = 126001993533349 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130400040044653) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65200020022226 + 65200020022227.

It is an arithmetic number, because the mean of its divisors is an integer number (65200020022227).

Almost surely, 2130400040044453 is an apocalyptic number.

It is an amenable number.

130400040044453 is a deficient number, since it is larger than the sum of its proper divisors (1).

130400040044453 is an equidigital number, since it uses as much as digits as its factorization.

130400040044453 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 46080, while the sum is 32.

Adding to 130400040044453 its reverse (354440040004031), we get a palindrome (484840080048484).

The spelling of 130400040044453 in words is "one hundred thirty trillion, four hundred billion, forty million, forty-four thousand, four hundred fifty-three".