13040104231032 has 16 divisors (see below), whose sum is σ = 32600260577640. Its totient is φ = 4346701410336.

The previous prime is 13040104230973. The next prime is 13040104231097. The reversal of 13040104231032 is 23013240104031.

It is a happy number.

13040104231032 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (24), and also a Moran number because the ratio is a prime number: 543337676293 = 13040104231032 / (1 + 3 + 0 + 4 + 0 + 1 + 0 + 4 + 2 + 3 + 1 + 0 + 3 + 2).

It is a junction number, because it is equal to n+sod(n) for n = 13040104230993 and 13040104231011.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 271668838123 + ... + 271668838170.

Almost surely, 2^{13040104231032} is an apocalyptic number.

13040104231032 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

13040104231032 is an abundant number, since it is smaller than the sum of its proper divisors (19560156346608).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13040104231032 is a wasteful number, since it uses less digits than its factorization.

13040104231032 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 543337676302 (or 543337676298 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 13040104231032 its reverse (23013240104031), we get a palindrome (36053344335063).

The spelling of 13040104231032 in words is "thirteen trillion, forty billion, one hundred four million, two hundred thirty-one thousand, thirty-two".