13040331444031 has 2 divisors, whose sum is σ = 13040331444032. Its totient is φ = 13040331444030.

The previous prime is 13040331443959. The next prime is 13040331444067. The reversal of 13040331444031 is 13044413304031.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13040331444031 - 2¹¹ = 13040331441983 is a prime.

It is a super-2 number, since 2×13040331444031² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13040331443984 and 13040331444002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13040331444731) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6520165722015 + 6520165722016.

It is an arithmetic number, because the mean of its divisors is an integer number (6520165722016).

Almost surely, 2^{13040331444031} is an apocalyptic number.

13040331444031 is a deficient number, since it is larger than the sum of its proper divisors (1).

13040331444031 is an equidigital number, since it uses as much as digits as its factorization.

13040331444031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 13040331444031 its reverse (13044413304031), we get a palindrome (26084744748062).

The spelling of 13040331444031 in words is "thirteen trillion, forty billion, three hundred thirty-one million, four hundred forty-four thousand, thirty-one".