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1304040253 is a prime number
BaseRepresentation
bin100110110111010…
…0001001100111101
310100212210002221011
41031232201030331
510132313242003
6333222035221
744213105425
oct11556411475
93325702834
101304040253
1160a10781a
12304878b11
1317a220c69
14c5293485
157973c46d
hex4dba133d

1304040253 has 2 divisors, whose sum is σ = 1304040254. Its totient is φ = 1304040252.

The previous prime is 1304040251. The next prime is 1304040259. The reversal of 1304040253 is 3520404031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1270423449 + 33616804 = 35643^2 + 5798^2 .

It is an emirp because it is prime and its reverse (3520404031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1304040253 - 21 = 1304040251 is a prime.

Together with 1304040251, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1304040251) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652020126 + 652020127.

It is an arithmetic number, because the mean of its divisors is an integer number (652020127).

Almost surely, 21304040253 is an apocalyptic number.

It is an amenable number.

1304040253 is a deficient number, since it is larger than the sum of its proper divisors (1).

1304040253 is an equidigital number, since it uses as much as digits as its factorization.

1304040253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 22.

The square root of 1304040253 is about 36111.4975181036. The cubic root of 1304040253 is about 1092.5223556667.

Adding to 1304040253 its reverse (3520404031), we get a palindrome (4824444284).

The spelling of 1304040253 in words is "one billion, three hundred four million, forty thousand, two hundred fifty-three".