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130404304421 is a prime number
BaseRepresentation
bin111100101110010110…
…0111100011000100101
3110110121002201001000122
41321130230330120211
54114032000220141
6135523520451325
712264353204306
oct1713454743045
9413532631018
10130404304421
1150338915016
1221334179b45
13c3b2892411
1464510707ad
1535d35c764b
hex1e5cb3c625

130404304421 has 2 divisors, whose sum is σ = 130404304422. Its totient is φ = 130404304420.

The previous prime is 130404304411. The next prime is 130404304423. The reversal of 130404304421 is 124403404031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 130310892196 + 93412225 = 360986^2 + 9665^2 .

It is a cyclic number.

It is not a de Polignac number, because 130404304421 - 222 = 130400110117 is a prime.

It is a super-2 number, since 2×1304043044212 (a number of 23 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 130404304423, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130404304423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65202152210 + 65202152211.

It is an arithmetic number, because the mean of its divisors is an integer number (65202152211).

Almost surely, 2130404304421 is an apocalyptic number.

It is an amenable number.

130404304421 is a deficient number, since it is larger than the sum of its proper divisors (1).

130404304421 is an equidigital number, since it uses as much as digits as its factorization.

130404304421 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4608, while the sum is 26.

Adding to 130404304421 its reverse (124403404031), we get a palindrome (254807708452).

The spelling of 130404304421 in words is "one hundred thirty billion, four hundred four million, three hundred four thousand, four hundred twenty-one".