Base | Representation |
---|---|
bin | 11101101001101000011111… |
… | …111010011000111000010110 |
3 | 122002201112101010211110200111 |
4 | 131221220133322120320112 |
5 | 114043021033101103420 |
6 | 1141202531233233234 |
7 | 36316254631562230 |
oct | 3551503772307026 |
9 | 562645333743614 |
10 | 130404332441110 |
11 | 38607192035772 |
12 | 1276129710281a |
13 | 579c0ca660b40 |
14 | 242b8638d1250 |
15 | 10121b14d345a |
hex | 769a1fe98e16 |
130404332441110 has 64 divisors (see below), whose sum is σ = 288898391577600. Its totient is φ = 41270444595072.
The previous prime is 130404332441087. The next prime is 130404332441167. The reversal of 130404332441110 is 11144233404031.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 109096071 + ... + 110284909.
It is an arithmetic number, because the mean of its divisors is an integer number (4514037368400).
Almost surely, 2130404332441110 is an apocalyptic number.
130404332441110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
130404332441110 is an abundant number, since it is smaller than the sum of its proper divisors (158494059136490).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130404332441110 is a wasteful number, since it uses less digits than its factorization.
130404332441110 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1309405.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 130404332441110 its reverse (11144233404031), we get a palindrome (141548565845141).
The spelling of 130404332441110 in words is "one hundred thirty trillion, four hundred four billion, three hundred thirty-two million, four hundred forty-one thousand, one hundred ten".
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