Base | Representation |
---|---|
bin | 1011110111000011011100… |
… | …0011010000011011101101 |
3 | 1201011122122222121102021012 |
4 | 2331300313003100123231 |
5 | 3202123312220430102 |
6 | 43422410350315005 |
7 | 2514066236516345 |
oct | 275606703203355 |
9 | 51148588542235 |
10 | 13040444311277 |
11 | 417846a939439 |
12 | 15673aa4b8a65 |
13 | 737929ac5256 |
14 | 33123760dd25 |
15 | 17932a186752 |
hex | bdc370d06ed |
13040444311277 has 2 divisors, whose sum is σ = 13040444311278. Its totient is φ = 13040444311276.
The previous prime is 13040444311273. The next prime is 13040444311351. The reversal of 13040444311277 is 77211344404031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9854865448516 + 3185578862761 = 3139246^2 + 1784819^2 .
It is a cyclic number.
It is not a de Polignac number, because 13040444311277 - 22 = 13040444311273 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13040444311273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6520222155638 + 6520222155639.
It is an arithmetic number, because the mean of its divisors is an integer number (6520222155639).
Almost surely, 213040444311277 is an apocalyptic number.
It is an amenable number.
13040444311277 is a deficient number, since it is larger than the sum of its proper divisors (1).
13040444311277 is an equidigital number, since it uses as much as digits as its factorization.
13040444311277 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 225792, while the sum is 41.
The spelling of 13040444311277 in words is "thirteen trillion, forty billion, four hundred forty-four million, three hundred eleven thousand, two hundred seventy-seven".
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