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13040444311351 is a prime number
BaseRepresentation
bin1011110111000011011100…
…0011010000011100110111
31201011122122222121102100221
42331300313003100130313
53202123312220430401
643422410350315211
72514066236516512
oct275606703203467
951148588542327
1013040444311351
11417846a9394a6
1215673aa4b8b07
13737929ac52b2
1433123760dd79
1517932a1867a1
hexbdc370d0737

13040444311351 has 2 divisors, whose sum is σ = 13040444311352. Its totient is φ = 13040444311350.

The previous prime is 13040444311277. The next prime is 13040444311369. The reversal of 13040444311351 is 15311344404031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13040444311351 - 221 = 13040442214199 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13040444311451) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6520222155675 + 6520222155676.

It is an arithmetic number, because the mean of its divisors is an integer number (6520222155676).

Almost surely, 213040444311351 is an apocalyptic number.

13040444311351 is a deficient number, since it is larger than the sum of its proper divisors (1).

13040444311351 is an equidigital number, since it uses as much as digits as its factorization.

13040444311351 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 34560, while the sum is 34.

Adding to 13040444311351 its reverse (15311344404031), we get a palindrome (28351788715382).

The spelling of 13040444311351 in words is "thirteen trillion, forty billion, four hundred forty-four million, three hundred eleven thousand, three hundred fifty-one".