Base | Representation |
---|---|
bin | 1011110111000011011100… |
… | …0011010000011100110111 |
3 | 1201011122122222121102100221 |
4 | 2331300313003100130313 |
5 | 3202123312220430401 |
6 | 43422410350315211 |
7 | 2514066236516512 |
oct | 275606703203467 |
9 | 51148588542327 |
10 | 13040444311351 |
11 | 417846a9394a6 |
12 | 15673aa4b8b07 |
13 | 737929ac52b2 |
14 | 33123760dd79 |
15 | 17932a1867a1 |
hex | bdc370d0737 |
13040444311351 has 2 divisors, whose sum is σ = 13040444311352. Its totient is φ = 13040444311350.
The previous prime is 13040444311277. The next prime is 13040444311369. The reversal of 13040444311351 is 15311344404031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13040444311351 - 221 = 13040442214199 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13040444311451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6520222155675 + 6520222155676.
It is an arithmetic number, because the mean of its divisors is an integer number (6520222155676).
Almost surely, 213040444311351 is an apocalyptic number.
13040444311351 is a deficient number, since it is larger than the sum of its proper divisors (1).
13040444311351 is an equidigital number, since it uses as much as digits as its factorization.
13040444311351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 34560, while the sum is 34.
Adding to 13040444311351 its reverse (15311344404031), we get a palindrome (28351788715382).
The spelling of 13040444311351 in words is "thirteen trillion, forty billion, four hundred forty-four million, three hundred eleven thousand, three hundred fifty-one".
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