13040444311301 has 16 divisors (see below), whose sum is σ = 14988176020800. Its totient is φ = 11220877324800.

The previous prime is 13040444311277. The next prime is 13040444311351. The reversal of 13040444311301 is 10311344404031.

It is not a de Polignac number, because 13040444311301 - 2²² = 13040440116997 is a prime.

It is a super-2 number, since 2×13040444311301² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13040444311351) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 27899180 + ... + 28362741.

It is an arithmetic number, because the mean of its divisors is an integer number (936761001300).

Almost surely, 2^{13040444311301} is an apocalyptic number.

13040444311301 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

13040444311301 is a deficient number, since it is larger than the sum of its proper divisors (1947731709499).

13040444311301 is a wasteful number, since it uses less digits than its factorization.

13040444311301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 56263060.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 13040444311301 its reverse (10311344404031), we get a palindrome (23351788715332).

The spelling of 13040444311301 in words is "thirteen trillion, forty billion, four hundred forty-four million, three hundred eleven thousand, three hundred one".