130405411132 has 24 divisors (see below), whose sum is σ = 238185916416. Its totient is φ = 62353585008.

The previous prime is 130405411099. The next prime is 130405411181. The reversal of 130405411132 is 231114504031.

It is a junction number, because it is equal to n+sod(n) for n = 130405411097 and 130405411106.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 249753 + ... + 568495.

It is an arithmetic number, because the mean of its divisors is an integer number (9924413184).

Almost surely, 2^130405411132 is an apocalyptic number.

It is an amenable number.

130405411132 is a deficient number, since it is larger than the sum of its proper divisors (107780505284).

130405411132 is a wasteful number, since it uses less digits than its factorization.

130405411132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 323217 (or 323215 counting only the distinct ones).

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 130405411132 its reverse (231114504031), we get a palindrome (361519915163).

The spelling of 130405411132 in words is "one hundred thirty billion, four hundred five million, four hundred eleven thousand, one hundred thirty-two".