Base | Representation |
---|---|
bin | 111100101110011100… |
… | …0101000000011101101 |
3 | 110110121022110121221112 |
4 | 1321130320220003231 |
5 | 4114033241220033 |
6 | 135524110241405 |
7 | 12264421220636 |
oct | 1713470500355 |
9 | 413538417845 |
10 | 130407366893 |
11 | 5033a616991 |
12 | 213351b6265 |
13 | c3b33c532b |
14 | 645162a88d |
15 | 35d39cec48 |
hex | 1e5ce280ed |
130407366893 has 2 divisors, whose sum is σ = 130407366894. Its totient is φ = 130407366892.
The previous prime is 130407366871. The next prime is 130407366961. The reversal of 130407366893 is 398663704031.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 128276436649 + 2130930244 = 358157^2 + 46162^2 .
It is a cyclic number.
It is not a de Polignac number, because 130407366893 - 28 = 130407366637 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130407369893) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65203683446 + 65203683447.
It is an arithmetic number, because the mean of its divisors is an integer number (65203683447).
Almost surely, 2130407366893 is an apocalyptic number.
It is an amenable number.
130407366893 is a deficient number, since it is larger than the sum of its proper divisors (1).
130407366893 is an equidigital number, since it uses as much as digits as its factorization.
130407366893 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1959552, while the sum is 50.
The spelling of 130407366893 in words is "one hundred thirty billion, four hundred seven million, three hundred sixty-six thousand, eight hundred ninety-three".
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