130410341444417 has 2 divisors, whose sum is σ = 130410341444418. Its totient is φ = 130410341444416.

The previous prime is 130410341444387. The next prime is 130410341444419. The reversal of 130410341444417 is 714444143014031.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 115754338048561 + 14656003395856 = 10758919^2 + 3828316^2 .

It is a cyclic number.

It is not a de Polignac number, because 130410341444417 - 2⁸ = 130410341444161 is a prime.

Together with 130410341444419, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (130410341444419) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65205170722208 + 65205170722209.

It is an arithmetic number, because the mean of its divisors is an integer number (65205170722209).

Almost surely, 2^{130410341444417} is an apocalyptic number.

It is an amenable number.

130410341444417 is a deficient number, since it is larger than the sum of its proper divisors (1).

130410341444417 is an equidigital number, since it uses as much as digits as its factorization.

130410341444417 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 258048, while the sum is 41.

Adding to 130410341444417 its reverse (714444143014031), we get a palindrome (844854484458448).

The spelling of 130410341444417 in words is "one hundred thirty trillion, four hundred ten billion, three hundred forty-one million, four hundred forty-four thousand, four hundred seventeen".