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1304116245247 is a prime number
BaseRepresentation
bin10010111110100011011…
…000101011001011111111
311121200011002210101011211
4102332203120223023333
5132331312224321442
62435034105025251
7163135134120364
oct22764330531377
94550132711154
101304116245247
11463088693172
121908b5a85227
1395c92b29a0a
144719611c46b
1523dca4ad617
hex12fa362b2ff

1304116245247 has 2 divisors, whose sum is σ = 1304116245248. Its totient is φ = 1304116245246.

The previous prime is 1304116245233. The next prime is 1304116245317. The reversal of 1304116245247 is 7425426114031.

It is a weak prime.

It is an emirp because it is prime and its reverse (7425426114031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1304116245247 - 27 = 1304116245119 is a prime.

It is a super-2 number, since 2×13041162452472 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1304116245217) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652058122623 + 652058122624.

It is an arithmetic number, because the mean of its divisors is an integer number (652058122624).

Almost surely, 21304116245247 is an apocalyptic number.

1304116245247 is a deficient number, since it is larger than the sum of its proper divisors (1).

1304116245247 is an equidigital number, since it uses as much as digits as its factorization.

1304116245247 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 161280, while the sum is 40.

The spelling of 1304116245247 in words is "one trillion, three hundred four billion, one hundred sixteen million, two hundred forty-five thousand, two hundred forty-seven".