Base | Representation |
---|---|
bin | 10010111110100011011… |
… | …000101011001011111111 |
3 | 11121200011002210101011211 |
4 | 102332203120223023333 |
5 | 132331312224321442 |
6 | 2435034105025251 |
7 | 163135134120364 |
oct | 22764330531377 |
9 | 4550132711154 |
10 | 1304116245247 |
11 | 463088693172 |
12 | 1908b5a85227 |
13 | 95c92b29a0a |
14 | 4719611c46b |
15 | 23dca4ad617 |
hex | 12fa362b2ff |
1304116245247 has 2 divisors, whose sum is σ = 1304116245248. Its totient is φ = 1304116245246.
The previous prime is 1304116245233. The next prime is 1304116245317. The reversal of 1304116245247 is 7425426114031.
It is a weak prime.
It is an emirp because it is prime and its reverse (7425426114031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1304116245247 - 27 = 1304116245119 is a prime.
It is a super-2 number, since 2×13041162452472 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1304116245217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652058122623 + 652058122624.
It is an arithmetic number, because the mean of its divisors is an integer number (652058122624).
Almost surely, 21304116245247 is an apocalyptic number.
1304116245247 is a deficient number, since it is larger than the sum of its proper divisors (1).
1304116245247 is an equidigital number, since it uses as much as digits as its factorization.
1304116245247 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 161280, while the sum is 40.
The spelling of 1304116245247 in words is "one trillion, three hundred four billion, one hundred sixteen million, two hundred forty-five thousand, two hundred forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •