1304116245317 has 2 divisors, whose sum is σ = 1304116245318. Its totient is φ = 1304116245316.

The previous prime is 1304116245247. The next prime is 1304116245319. The reversal of 1304116245317 is 7135426114031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 885162970561 + 418953274756 = 940831^2 + 647266^2 .

It is an emirp because it is prime and its reverse (7135426114031) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1304116245317 is a prime.

Together with 1304116245319, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1304116245319) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652058122658 + 652058122659.

It is an arithmetic number, because the mean of its divisors is an integer number (652058122659).

Almost surely, 2^{1304116245317} is an apocalyptic number.

It is an amenable number.

1304116245317 is a deficient number, since it is larger than the sum of its proper divisors (1).

1304116245317 is an equidigital number, since it uses as much as digits as its factorization.

1304116245317 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60480, while the sum is 38.

The spelling of 1304116245317 in words is "one trillion, three hundred four billion, one hundred sixteen million, two hundred forty-five thousand, three hundred seventeen".