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13041201127 is a prime number
BaseRepresentation
bin11000010010101000…
…01110111111100111
31020122212022122210011
430021110032333213
5203202021414002
65554022111051
7641113244353
oct141124167747
936585278704
1013041201127
115592466479
12263b57b487
1312caa99176
148ba012463
15514d8e8d7
hex30950efe7

13041201127 has 2 divisors, whose sum is σ = 13041201128. Its totient is φ = 13041201126.

The previous prime is 13041201097. The next prime is 13041201137. The reversal of 13041201127 is 72110214031.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13041201127 - 215 = 13041168359 is a prime.

It is a super-3 number, since 3×130412011273 (a number of 31 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13041201098 and 13041201107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13041201137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6520600563 + 6520600564.

It is an arithmetic number, because the mean of its divisors is an integer number (6520600564).

Almost surely, 213041201127 is an apocalyptic number.

13041201127 is a deficient number, since it is larger than the sum of its proper divisors (1).

13041201127 is an equidigital number, since it uses as much as digits as its factorization.

13041201127 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 336, while the sum is 22.

Adding to 13041201127 its reverse (72110214031), we get a palindrome (85151415158).

The spelling of 13041201127 in words is "thirteen billion, forty-one million, two hundred one thousand, one hundred twenty-seven".