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1304122444111 is a prime number
BaseRepresentation
bin10010111110100011110…
…000010100100101001111
311121200011112110022102101
4102332203300110211033
5132331320321202421
62435034445535531
7163135240606024
oct22764360244517
94550145408371
101304122444111
114630911374a3
121908b7b745a7
1395c941ba396
1447196c9354b
1523dcacd5191
hex12fa3c1494f

1304122444111 has 2 divisors, whose sum is σ = 1304122444112. Its totient is φ = 1304122444110.

The previous prime is 1304122444061. The next prime is 1304122444151. The reversal of 1304122444111 is 1114442214031.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1304122444111 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1304122444111.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1304122444151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652061222055 + 652061222056.

It is an arithmetic number, because the mean of its divisors is an integer number (652061222056).

Almost surely, 21304122444111 is an apocalyptic number.

1304122444111 is a deficient number, since it is larger than the sum of its proper divisors (1).

1304122444111 is an equidigital number, since it uses as much as digits as its factorization.

1304122444111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3072, while the sum is 28.

Adding to 1304122444111 its reverse (1114442214031), we get a palindrome (2418564658142).

The spelling of 1304122444111 in words is "one trillion, three hundred four billion, one hundred twenty-two million, four hundred forty-four thousand, one hundred eleven".