Base | Representation |
---|---|
bin | 1011110111000110011000… |
… | …0101001010011011100010 |
3 | 1201011201200222022020101001 |
4 | 2331301212011022123202 |
5 | 3202131421213341010 |
6 | 43423020534102214 |
7 | 2514124630250122 |
oct | 275614605123342 |
9 | 51151628266331 |
10 | 13041233340130 |
11 | 41788352664a6 |
12 | 156758a7aa96a |
13 | 737a24406528 |
14 | 3312b0320c82 |
15 | 179374592c3a |
hex | bdc6614a6e2 |
13041233340130 has 64 divisors (see below), whose sum is σ = 24198141242880. Its totient is φ = 5057717946624.
The previous prime is 13041233340119. The next prime is 13041233340131. The reversal of 13041233340130 is 3104333214031.
13041233340130 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not an unprimeable number, because it can be changed into a prime (13041233340131) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 314172837 + ... + 314214343.
It is an arithmetic number, because the mean of its divisors is an integer number (378095956920).
Almost surely, 213041233340130 is an apocalyptic number.
13041233340130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13041233340130 is a deficient number, since it is larger than the sum of its proper divisors (11156907902750).
13041233340130 is a wasteful number, since it uses less digits than its factorization.
13041233340130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47803.
The product of its (nonzero) digits is 7776, while the sum is 28.
Adding to 13041233340130 its reverse (3104333214031), we get a palindrome (16145566554161).
The spelling of 13041233340130 in words is "thirteen trillion, forty-one billion, two hundred thirty-three million, three hundred forty thousand, one hundred thirty".
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