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1304142341023 is a prime number
BaseRepresentation
bin10010111110100100111…
…100001110001110011111
311121200012220220011212001
4102332210330032032133
5132331340414403043
62435040440223131
7163135601665354
oct22764474161637
94550186804761
101304142341023
114630a1397325
1219090276aaa7
1395c983658c2
144719979262b
1523dcc91574d
hex12fa4f0e39f

1304142341023 has 2 divisors, whose sum is σ = 1304142341024. Its totient is φ = 1304142341022.

The previous prime is 1304142341017. The next prime is 1304142341041. The reversal of 1304142341023 is 3201432414031.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1304142341023 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1304142340982 and 1304142341000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1304142341053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652071170511 + 652071170512.

It is an arithmetic number, because the mean of its divisors is an integer number (652071170512).

Almost surely, 21304142341023 is an apocalyptic number.

1304142341023 is a deficient number, since it is larger than the sum of its proper divisors (1).

1304142341023 is an equidigital number, since it uses as much as digits as its factorization.

1304142341023 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 1304142341023 its reverse (3201432414031), we get a palindrome (4505574755054).

It can be divided in two parts, 13041 and 42341023, that added together give a square (42354064 = 65082).

The spelling of 1304142341023 in words is "one trillion, three hundred four billion, one hundred forty-two million, three hundred forty-one thousand, twenty-three".