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13041911 is a prime number
BaseRepresentation
bin110001110000…
…000011110111
3220112121010202
4301300003313
511314320121
61143311115
7215566031
oct61600367
926477122
1013041911
1173a8643
12444b49b
13291830c
141a36c51
15122940b
hexc700f7

13041911 has 2 divisors, whose sum is σ = 13041912. Its totient is φ = 13041910.

The previous prime is 13041901. The next prime is 13041913. The reversal of 13041911 is 11914031.

13041911 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (11914031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13041911 - 214 = 13025527 is a prime.

Together with 13041913, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13041913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6520955 + 6520956.

It is an arithmetic number, because the mean of its divisors is an integer number (6520956).

Almost surely, 213041911 is an apocalyptic number.

13041911 is a deficient number, since it is larger than the sum of its proper divisors (1).

13041911 is an equidigital number, since it uses as much as digits as its factorization.

13041911 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 20.

The square root of 13041911 is about 3611.3586086126. The cubic root of 13041911 is about 235.3858817848.

Adding to 13041911 its reverse (11914031), we get a palindrome (24955942).

The spelling of 13041911 in words is "thirteen million, forty-one thousand, nine hundred eleven".