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1304222441149 is a prime number
BaseRepresentation
bin10010111110101001101…
…101110001111010111101
311121200102111121200120101
4102332221231301322331
5132332021421104044
62435052421121101
7163140563556415
oct22765155617275
94550374550511
101304222441149
11463132626781
12190925559191
1395cabb2c724
14471a6283645
1523dd4988cd4
hex12fa9b71ebd

1304222441149 has 2 divisors, whose sum is σ = 1304222441150. Its totient is φ = 1304222441148.

The previous prime is 1304222441129. The next prime is 1304222441153. The reversal of 1304222441149 is 9411442224031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1128921125049 + 175301316100 = 1062507^2 + 418690^2 .

It is an emirp because it is prime and its reverse (9411442224031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1304222441149 - 25 = 1304222441117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1304222441129) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652111220574 + 652111220575.

It is an arithmetic number, because the mean of its divisors is an integer number (652111220575).

Almost surely, 21304222441149 is an apocalyptic number.

It is an amenable number.

1304222441149 is a deficient number, since it is larger than the sum of its proper divisors (1).

1304222441149 is an equidigital number, since it uses as much as digits as its factorization.

1304222441149 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 55296, while the sum is 37.

The spelling of 1304222441149 in words is "one trillion, three hundred four billion, two hundred twenty-two million, four hundred forty-one thousand, one hundred forty-nine".