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1304222441153 is a prime number
BaseRepresentation
bin10010111110101001101…
…101110001111011000001
311121200102111121200120112
4102332221231301323001
5132332021421104103
62435052421121105
7163140563556422
oct22765155617301
94550374550515
101304222441153
11463132626785
12190925559195
1395cabb2c728
14471a6283649
1523dd4988cd8
hex12fa9b71ec1

1304222441153 has 2 divisors, whose sum is σ = 1304222441154. Its totient is φ = 1304222441152.

The previous prime is 1304222441149. The next prime is 1304222441309. The reversal of 1304222441153 is 3511442224031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1300220233984 + 4002207169 = 1140272^2 + 63263^2 .

It is a cyclic number.

It is not a de Polignac number, because 1304222441153 - 22 = 1304222441149 is a prime.

It is not a weakly prime, because it can be changed into another prime (1304222441113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652111220576 + 652111220577.

It is an arithmetic number, because the mean of its divisors is an integer number (652111220577).

Almost surely, 21304222441153 is an apocalyptic number.

It is an amenable number.

1304222441153 is a deficient number, since it is larger than the sum of its proper divisors (1).

1304222441153 is an equidigital number, since it uses as much as digits as its factorization.

1304222441153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 23040, while the sum is 32.

Adding to 1304222441153 its reverse (3511442224031), we get a palindrome (4815664665184).

The spelling of 1304222441153 in words is "one trillion, three hundred four billion, two hundred twenty-two million, four hundred forty-one thousand, one hundred fifty-three".