Base | Representation |
---|---|
bin | 10010111110101010110… |
… | …101000101010111001000 |
3 | 11121200110210210022222011 |
4 | 102332222311011113020 |
5 | 132332041212224000 |
6 | 2435054325505304 |
7 | 163141211466541 |
oct | 22765265052710 |
9 | 4550423708864 |
10 | 1304241133000 |
11 | 463142133193 |
12 | 19092b872234 |
13 | 95cb29755b0 |
14 | 471a894b4c8 |
15 | 23dd642c2ba |
hex | 12faad455c8 |
1304241133000 has 64 divisors (see below), whose sum is σ = 3286687687920. Its totient is φ = 481565952000.
The previous prime is 1304241132917. The next prime is 1304241133001. The reversal of 1304241133000 is 3311424031.
It can be written as a sum of positive squares in 8 ways, for example, as 46205222116 + 1258035910884 = 214954^2 + 1121622^2 .
It is not an unprimeable number, because it can be changed into a prime (1304241133001) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 50150121 + ... + 50176120.
Almost surely, 21304241133000 is an apocalyptic number.
1304241133000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1304241133000 is an abundant number, since it is smaller than the sum of its proper divisors (1982446554920).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1304241133000 is a wasteful number, since it uses less digits than its factorization.
1304241133000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 100326275 (or 100326261 counting only the distinct ones).
The product of its (nonzero) digits is 864, while the sum is 22.
Adding to 1304241133000 its reverse (3311424031), we get a palindrome (1307552557031).
The spelling of 1304241133000 in words is "one trillion, three hundred four billion, two hundred forty-one million, one hundred thirty-three thousand".
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