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1304242319 is a prime number
BaseRepresentation
bin100110110111101…
…0010100010001111
310100220011101010002
41031233102202033
510132341223234
6333230234515
744214606512
oct11557224217
93326141102
101304242319
1160a235616
12304955a3b
1317a291c23
14c5306d79
157977c27e
hex4dbd288f

1304242319 has 2 divisors, whose sum is σ = 1304242320. Its totient is φ = 1304242318.

The previous prime is 1304242307. The next prime is 1304242321. The reversal of 1304242319 is 9132424031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1304242319 - 28 = 1304242063 is a prime.

It is a super-2 number, since 2×13042423192 = 3402096053340995522, which contains 22 as substring.

It is a Sophie Germain prime.

Together with 1304242321, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1304242291 and 1304242300.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1304242399) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652121159 + 652121160.

It is an arithmetic number, because the mean of its divisors is an integer number (652121160).

Almost surely, 21304242319 is an apocalyptic number.

1304242319 is a deficient number, since it is larger than the sum of its proper divisors (1).

1304242319 is an equidigital number, since it uses as much as digits as its factorization.

1304242319 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 29.

The square root of 1304242319 is about 36114.2952167144. The cubic root of 1304242319 is about 1092.5787829178.

The spelling of 1304242319 in words is "one billion, three hundred four million, two hundred forty-two thousand, three hundred nineteen".