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1304242533551 is a prime number
BaseRepresentation
bin10010111110101010111…
…010011011010010101111
311121200110220102111011102
4102332222322123102233
5132332042042033201
62435054415513315
7163141226422016
oct22765272332257
94550426374142
101304242533551
114631429aa471
1219093022883b
1395cb3045c19
14471a8bd3a7d
1523dd660726b
hex12faae9b4af

1304242533551 has 2 divisors, whose sum is σ = 1304242533552. Its totient is φ = 1304242533550.

The previous prime is 1304242533467. The next prime is 1304242533569. The reversal of 1304242533551 is 1553352424031.

It is a strong prime.

It is an emirp because it is prime and its reverse (1553352424031) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1304242533551 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1304242533571) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652121266775 + 652121266776.

It is an arithmetic number, because the mean of its divisors is an integer number (652121266776).

Almost surely, 21304242533551 is an apocalyptic number.

1304242533551 is a deficient number, since it is larger than the sum of its proper divisors (1).

1304242533551 is an equidigital number, since it uses as much as digits as its factorization.

1304242533551 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216000, while the sum is 38.

Adding to 1304242533551 its reverse (1553352424031), we get a palindrome (2857594957582).

The spelling of 1304242533551 in words is "one trillion, three hundred four billion, two hundred forty-two million, five hundred thirty-three thousand, five hundred fifty-one".