Base | Representation |
---|---|
bin | 10010111110101010111… |
… | …101000101101001111001 |
3 | 11121200110221201221100221 |
4 | 102332222331011221321 |
5 | 132332042231400403 |
6 | 2435054442500041 |
7 | 163141235356306 |
oct | 22765275055171 |
9 | 4550427657327 |
10 | 1304243231353 |
11 | 463143336767 |
12 | 190930504621 |
13 | 95cb322b71a |
14 | 471a8d360ad |
15 | 23dd66e3dbd |
hex | 12faaf45a79 |
1304243231353 has 2 divisors, whose sum is σ = 1304243231354. Its totient is φ = 1304243231352.
The previous prime is 1304243231323. The next prime is 1304243231413. The reversal of 1304243231353 is 3531323424031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1286743116409 + 17500114944 = 1134347^2 + 132288^2 .
It is a cyclic number.
It is not a de Polignac number, because 1304243231353 - 25 = 1304243231321 is a prime.
It is not a weakly prime, because it can be changed into another prime (1304243231303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652121615676 + 652121615677.
It is an arithmetic number, because the mean of its divisors is an integer number (652121615677).
Almost surely, 21304243231353 is an apocalyptic number.
It is an amenable number.
1304243231353 is a deficient number, since it is larger than the sum of its proper divisors (1).
1304243231353 is an equidigital number, since it uses as much as digits as its factorization.
1304243231353 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 77760, while the sum is 34.
Adding to 1304243231353 its reverse (3531323424031), we get a palindrome (4835566655384).
The spelling of 1304243231353 in words is "one trillion, three hundred four billion, two hundred forty-three million, two hundred thirty-one thousand, three hundred fifty-three".
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