Base | Representation |
---|---|
bin | 10010111110101010111… |
… | …101000101101010110101 |
3 | 11121200110221201221110011 |
4 | 102332222331011222311 |
5 | 132332042231401123 |
6 | 2435054442500221 |
7 | 163141235356423 |
oct | 22765275055265 |
9 | 4550427657404 |
10 | 1304243231413 |
11 | 463143336811 |
12 | 190930504671 |
13 | 95cb322b765 |
14 | 471a8d36113 |
15 | 23dd66e3e0d |
hex | 12faaf45ab5 |
1304243231413 has 2 divisors, whose sum is σ = 1304243231414. Its totient is φ = 1304243231412.
The previous prime is 1304243231353. The next prime is 1304243231461. The reversal of 1304243231413 is 3141323424031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1285282492209 + 18960739204 = 1133703^2 + 137698^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1304243231413 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1304243271413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652121615706 + 652121615707.
It is an arithmetic number, because the mean of its divisors is an integer number (652121615707).
Almost surely, 21304243231413 is an apocalyptic number.
It is an amenable number.
1304243231413 is a deficient number, since it is larger than the sum of its proper divisors (1).
1304243231413 is an equidigital number, since it uses as much as digits as its factorization.
1304243231413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 1304243231413 its reverse (3141323424031), we get a palindrome (4445566655444).
The spelling of 1304243231413 in words is "one trillion, three hundred four billion, two hundred forty-three million, two hundred thirty-one thousand, four hundred thirteen".
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