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1304253505133 is a prime number
BaseRepresentation
bin10010111110101011100…
…100010001111001101101
311121200111200001220100022
4102332223210101321231
5132332102344131013
62435055451011525
7163141421606105
oct22765344217155
94550450056308
101304253505133
11463149113597
12190933a39ba5
1395cb53b7a97
14471aa44c205
1523dd7573008
hex12fab911e6d

1304253505133 has 2 divisors, whose sum is σ = 1304253505134. Its totient is φ = 1304253505132.

The previous prime is 1304253505127. The next prime is 1304253505169. The reversal of 1304253505133 is 3315053524031.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 814446686089 + 489806819044 = 902467^2 + 699862^2 .

It is a cyclic number.

It is not a de Polignac number, because 1304253505133 - 26 = 1304253505069 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1304253505093 and 1304253505102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1304253505333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652126752566 + 652126752567.

It is an arithmetic number, because the mean of its divisors is an integer number (652126752567).

Almost surely, 21304253505133 is an apocalyptic number.

It is an amenable number.

1304253505133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1304253505133 is an equidigital number, since it uses as much as digits as its factorization.

1304253505133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 81000, while the sum is 35.

The spelling of 1304253505133 in words is "one trillion, three hundred four billion, two hundred fifty-three million, five hundred five thousand, one hundred thirty-three".