Base | Representation |
---|---|
bin | 10010111110101011100… |
… | …100010001111011110111 |
3 | 11121200111200001220112102 |
4 | 102332223210101323313 |
5 | 132332102344132041 |
6 | 2435055451012315 |
7 | 163141421606363 |
oct | 22765344217367 |
9 | 4550450056472 |
10 | 1304253505271 |
11 | 463149113702 |
12 | 190933a3a09b |
13 | 95cb53b7b72 |
14 | 471aa44c2a3 |
15 | 23dd757309b |
hex | 12fab911ef7 |
1304253505271 has 2 divisors, whose sum is σ = 1304253505272. Its totient is φ = 1304253505270.
The previous prime is 1304253505237. The next prime is 1304253505279. The reversal of 1304253505271 is 1725053524031.
It is a strong prime.
It is an emirp because it is prime and its reverse (1725053524031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1304253505271 - 26 = 1304253505207 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1304253505279) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652126752635 + 652126752636.
It is an arithmetic number, because the mean of its divisors is an integer number (652126752636).
Almost surely, 21304253505271 is an apocalyptic number.
1304253505271 is a deficient number, since it is larger than the sum of its proper divisors (1).
1304253505271 is an equidigital number, since it uses as much as digits as its factorization.
1304253505271 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 126000, while the sum is 38.
The spelling of 1304253505271 in words is "one trillion, three hundred four billion, two hundred fifty-three million, five hundred five thousand, two hundred seventy-one".
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