Base | Representation |
---|---|
bin | 1011110111001101000000… |
… | …0110100110111101100111 |
3 | 1201011220021221100210201211 |
4 | 2331303100012212331213 |
5 | 3202144042044312124 |
6 | 43423513235132251 |
7 | 2514216666426541 |
oct | 275632006467547 |
9 | 51156257323654 |
10 | 13043012104039 |
11 | 4179568336115 |
12 | 15679a6444087 |
13 | 737c48a9c658 |
14 | 3313dc66a691 |
15 | 17942a803e94 |
hex | bdcd01a6f67 |
13043012104039 has 2 divisors, whose sum is σ = 13043012104040. Its totient is φ = 13043012104038.
The previous prime is 13043012103941. The next prime is 13043012104049. The reversal of 13043012104039 is 93040121034031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13043012104039 - 27 = 13043012103911 is a prime.
It is a super-2 number, since 2×130430121040392 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13043012104039.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13043012104049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6521506052019 + 6521506052020.
It is an arithmetic number, because the mean of its divisors is an integer number (6521506052020).
Almost surely, 213043012104039 is an apocalyptic number.
13043012104039 is a deficient number, since it is larger than the sum of its proper divisors (1).
13043012104039 is an equidigital number, since it uses as much as digits as its factorization.
13043012104039 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7776, while the sum is 31.
The spelling of 13043012104039 in words is "thirteen trillion, forty-three billion, twelve million, one hundred four thousand, thirty-nine".
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