13043012103941 has 2 divisors, whose sum is σ = 13043012103942. Its totient is φ = 13043012103940.

The previous prime is 13043012103929. The next prime is 13043012104039. The reversal of 13043012103941 is 14930121034031.

13043012103941 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6963508211716 + 6079503892225 = 2638846^2 + 2465665^2 .

It is a cyclic number.

It is not a de Polignac number, because 13043012103941 - 2²⁶ = 13042944995077 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13043012103898 and 13043012103907.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13043012103911) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6521506051970 + 6521506051971.

It is an arithmetic number, because the mean of its divisors is an integer number (6521506051971).

Almost surely, 2^{13043012103941} is an apocalyptic number.

It is an amenable number.

13043012103941 is a deficient number, since it is larger than the sum of its proper divisors (1).

13043012103941 is an equidigital number, since it uses as much as digits as its factorization.

13043012103941 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7776, while the sum is 32.

Adding to 13043012103941 its reverse (14930121034031), we get a palindrome (27973133137972).

The spelling of 13043012103941 in words is "thirteen trillion, forty-three billion, twelve million, one hundred three thousand, nine hundred forty-one".