130430400123281 has 2 divisors, whose sum is σ = 130430400123282. Its totient is φ = 130430400123280.

The previous prime is 130430400123269. The next prime is 130430400123293. The reversal of 130430400123281 is 182321004034031.

It is a balanced prime because it is at equal distance from previous prime (130430400123269) and next prime (130430400123293).

It can be written as a sum of positive squares in only one way, i.e., 122567395272256 + 7863004851025 = 11071016^2 + 2804105^2 .

It is an emirp because it is prime and its reverse (182321004034031) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-130430400123281 is a prime.

It is a super-2 number, since 2×130430400123281² (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (130430400123481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65215200061640 + 65215200061641.

It is an arithmetic number, because the mean of its divisors is an integer number (65215200061641).

Almost surely, 2^{130430400123281} is an apocalyptic number.

It is an amenable number.

130430400123281 is a deficient number, since it is larger than the sum of its proper divisors (1).

130430400123281 is an equidigital number, since it uses as much as digits as its factorization.

130430400123281 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 32.

The spelling of 130430400123281 in words is "one hundred thirty trillion, four hundred thirty billion, four hundred million, one hundred twenty-three thousand, two hundred eighty-one".