130430403223121 has 2 divisors, whose sum is σ = 130430403223122. Its totient is φ = 130430403223120.

The previous prime is 130430403223091. The next prime is 130430403223123. The reversal of 130430403223121 is 121322304034031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 122101638101521 + 8328765121600 = 11049961^2 + 2885960^2 .

It is a cyclic number.

It is not a de Polignac number, because 130430403223121 - 2³⁴ = 130413223353937 is a prime.

Together with 130430403223123, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (130430403223123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65215201611560 + 65215201611561.

It is an arithmetic number, because the mean of its divisors is an integer number (65215201611561).

Almost surely, 2^{130430403223121} is an apocalyptic number.

It is an amenable number.

130430403223121 is a deficient number, since it is larger than the sum of its proper divisors (1).

130430403223121 is an equidigital number, since it uses as much as digits as its factorization.

130430403223121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 130430403223121 its reverse (121322304034031), we get a palindrome (251752707257152).

The spelling of 130430403223121 in words is "one hundred thirty trillion, four hundred thirty billion, four hundred three million, two hundred twenty-three thousand, one hundred twenty-one".