13043104420 has 48 divisors (see below), whose sum is σ = 29445615360. Its totient is φ = 4837480704.

The previous prime is 13043104411. The next prime is 13043104421. The reversal of 13043104420 is 2440134031.

It is a super-2 number, since 2×13043104420² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13043104391 and 13043104400.

It is not an unprimeable number, because it can be changed into a prime (13043104421) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 347289 + ... + 383008.

It is an arithmetic number, because the mean of its divisors is an integer number (613450320).

Almost surely, 2^13043104420 is an apocalyptic number.

13043104420 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13043104420 is an abundant number, since it is smaller than the sum of its proper divisors (16402510940).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13043104420 is a wasteful number, since it uses less digits than its factorization.

13043104420 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 730372 (or 730370 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 13043104420 its reverse (2440134031), we get a palindrome (15483238451).

The spelling of 13043104420 in words is "thirteen billion, forty-three million, one hundred four thousand, four hundred twenty".