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130431342403223 is a prime number
BaseRepresentation
bin11101101010000001101001…
…110101001101111010010111
3122002211010002111211201011122
4131222001221311031322113
5114043441342123400343
61141223155334354155
736321232153506401
oct3552015165157227
9562733074751148
10130431342403223
11386176924a3004
12127665747bb95b
1357a181341bc44
14242cca6ba7b71
151012c42885068
hex76a069d4de97

130431342403223 has 2 divisors, whose sum is σ = 130431342403224. Its totient is φ = 130431342403222.

The previous prime is 130431342403199. The next prime is 130431342403247. The reversal of 130431342403223 is 322304243134031.

It is a balanced prime because it is at equal distance from previous prime (130431342403199) and next prime (130431342403247).

It is a cyclic number.

It is not a de Polignac number, because 130431342403223 - 240 = 129331830775447 is a prime.

It is a super-2 number, since 2×1304313424032232 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130431342403253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65215671201611 + 65215671201612.

It is an arithmetic number, because the mean of its divisors is an integer number (65215671201612).

Almost surely, 2130431342403223 is an apocalyptic number.

130431342403223 is a deficient number, since it is larger than the sum of its proper divisors (1).

130431342403223 is an equidigital number, since it uses as much as digits as its factorization.

130431342403223 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 124416, while the sum is 35.

Adding to 130431342403223 its reverse (322304243134031), we get a palindrome (452735585537254).

The spelling of 130431342403223 in words is "one hundred thirty trillion, four hundred thirty-one billion, three hundred forty-two million, four hundred three thousand, two hundred twenty-three".