130433001432432 has 20 divisors (see below), whose sum is σ = 336951920367240. Its totient is φ = 43477667144128.

The previous prime is 130433001432341. The next prime is 130433001432497. The reversal of 130433001432432 is 234234100334031.

It is a happy number.

130433001432432 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.

It is a super-3 number, since 3×130433001432432³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 130433001432393 and 130433001432402.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1358677098207 + ... + 1358677098302.

It is an arithmetic number, because the mean of its divisors is an integer number (16847596018362).

Almost surely, 2^{130433001432432} is an apocalyptic number.

130433001432432 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

130433001432432 is an abundant number, since it is smaller than the sum of its proper divisors (206518918934808).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130433001432432 is a wasteful number, since it uses less digits than its factorization.

130433001432432 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2717354196520 (or 2717354196514 counting only the distinct ones).

The product of its (nonzero) digits is 62208, while the sum is 33.

Adding to 130433001432432 its reverse (234234100334031), we get a palindrome (364667101766463).

The spelling of 130433001432432 in words is "one hundred thirty trillion, four hundred thirty-three billion, one million, four hundred thirty-two thousand, four hundred thirty-two".