1304332454441 has 2 divisors, whose sum is σ = 1304332454442. Its totient is φ = 1304332454440.

The previous prime is 1304332454429. The next prime is 1304332454443. The reversal of 1304332454441 is 1444542334031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1304164000000 + 168454441 = 1142000^2 + 12979^2 .

It is a cyclic number.

It is not a de Polignac number, because 1304332454441 - 2¹⁸ = 1304332192297 is a prime.

Together with 1304332454443, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1304332454395 and 1304332454404.

It is not a weakly prime, because it can be changed into another prime (1304332454443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652166227220 + 652166227221.

It is an arithmetic number, because the mean of its divisors is an integer number (652166227221).

Almost surely, 2^{1304332454441} is an apocalyptic number.

It is an amenable number.

1304332454441 is a deficient number, since it is larger than the sum of its proper divisors (1).

1304332454441 is an equidigital number, since it uses as much as digits as its factorization.

1304332454441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 276480, while the sum is 38.

Adding to 1304332454441 its reverse (1444542334031), we get a palindrome (2748874788472).

The spelling of 1304332454441 in words is "one trillion, three hundred four billion, three hundred thirty-two million, four hundred fifty-four thousand, four hundred forty-one".