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130434400121317 is a prime number
BaseRepresentation
bin11101101010000100100000…
…000101011111000111100101
3122002211101222121110212211221
4131222010200011133013211
5114044014122412340232
61141224423004100341
736321401012623405
oct3552044005370745
9562741877425757
10130434400121317
1138618a114a5956
12127670888346b1
1357a1baca618a6
14242d0b6d16805
151012d7102a897
hex76a12015f1e5

130434400121317 has 2 divisors, whose sum is σ = 130434400121318. Its totient is φ = 130434400121316.

The previous prime is 130434400121287. The next prime is 130434400121353. The reversal of 130434400121317 is 713121004434031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 106793498800836 + 23640901320481 = 10334094^2 + 4862191^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130434400121317 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130434400121387) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65217200060658 + 65217200060659.

It is an arithmetic number, because the mean of its divisors is an integer number (65217200060659).

Almost surely, 2130434400121317 is an apocalyptic number.

It is an amenable number.

130434400121317 is a deficient number, since it is larger than the sum of its proper divisors (1).

130434400121317 is an equidigital number, since it uses as much as digits as its factorization.

130434400121317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24192, while the sum is 34.

Adding to 130434400121317 its reverse (713121004434031), we get a palindrome (843555404555348).

The spelling of 130434400121317 in words is "one hundred thirty trillion, four hundred thirty-four billion, four hundred million, one hundred twenty-one thousand, three hundred seventeen".