13043440411340 has 24 divisors (see below), whose sum is σ = 27394215230592. Its totient is φ = 5216806570880.

The previous prime is 13043440411333. The next prime is 13043440411387. The reversal of 13043440411340 is 4311404434031.

It is a super-4 number, since 4×13043440411340⁴ (a number of 54 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13043440411297 and 13043440411306.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 35411804 + ... + 35778243.

It is an arithmetic number, because the mean of its divisors is an integer number (1141425634608).

Almost surely, 2^{13043440411340} is an apocalyptic number.

13043440411340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13043440411340 is an abundant number, since it is smaller than the sum of its proper divisors (14350774819252).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13043440411340 is a wasteful number, since it uses less digits than its factorization.

13043440411340 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 71199217 (or 71199215 counting only the distinct ones).

The product of its (nonzero) digits is 27648, while the sum is 32.

Adding to 13043440411340 its reverse (4311404434031), we get a palindrome (17354844845371).

The spelling of 13043440411340 in words is "thirteen trillion, forty-three billion, four hundred forty million, four hundred eleven thousand, three hundred forty".